Experiment 8 Torques, Equilibrium, and Center of Gravity 1/4/2022 Student Name: Section Number. Instructions 1) Follow all of the lab activity steps given in the Lab Procedure. 2) Attach your completed data tables to this page. 3) TYPE YOUR ANSWERS IN THE PROVIDED SPACES below & in your data tables. 4) Attach additional sheets of paper that clearly (NEATLY) show all of your calculations performed during this experiment Results 1) In PART A the weight of the meter stick is not included in the calculation of CW and CCW torque. Why? Would the mass of the meter stick need to be included if it was in equilibrium but NOT horizontal? (This means the meter stick is at an angle but not moving. Hint: Use the general definition of t!) Write out your answer in a clear and well supported paragraph. erase this and type in your answer 2) What is the percentage difference between your CW and CCW torque magnitudes in PART A, B, & C? What is the most likely source of measurement error in this experiment? Write out your answer in a clear and well supported paragraph. erase this and type in your answerA. Rigid Rod Supported at its Center of Gravity Force = mubs . a Table 10.1 . labslotedifference, 1 100 m2 = 0121K9 Averycor mean ma = 0.06Ka m kg Case X 1 X 2 10 cm orque rim, 9 = rym2 2 CW CCW % Diff 0.3 m Q. 57 0. 324Nm 0.372 Nm 0. 8 0% rit CW = r,mig X 1 X 2 X 3 = (0.3) (0, 11) (9.81) 2 Torque = 0 . 324 N m CW CCW % Diff CCW = Yz mzy 0.35 m 0.25m 1 6.233 0.515Nm|0. 515No = (8. 157 ) (0. 21) (9.81 cloc wise Ig mag trimg= rimA = 0, 323 NM B. Rigid Rod Supported at Different Points m 2 Table 10.2 center = 28.8 cm 12 = 100. cm - 28. 8 cm = 71.2 cm mass off ms =148719 4 = 146. 72 - 1 487 9/cm m 2 =0. lobkg 100 cm ma= 0.0 428K X, = 10ocm - 28.8 cm 64. 40m X 1 X 2 X 3 my = 71. 20m ( 1. (ofglem ) = 06 2 A m 0. buym 0. 144 m Torque X3 - 28.8 = 14.4 cm CW CCW % Diff 2 1. 28 8m/2 . 856m 10. 14/m|0.571 0,519 13 - 28. 8 cm - 14 x 40 m = 14. 4cm CW CW ma = 28. 8 om ( 1 . 4879 1 (m) C. Center of Gravity = 42.8286 = 42. 8 9 Table 10.3 mr = cat. 8 9 + 109 + 1418.79 m . = 01 ka In 423. 52 ms Torque umm 9 2 cm C CW CCW % Diff mi @ 98 cm 0. 1188 m 10. 16 4m | 0. 6 2 810 . 678 NO . 6 8INm o . 94%%