Explain what it means to say that lim f(x) = 5 and lim f(x) = 4. x _ 9- O As x approaches 9 from the left, f(x) approaches 5. As x approaches 9 from the right, f(x) approaches 4. O As x approaches 9, f(x) approaches 4, but f(9) = 5. O As x approaches 9 from the right, f(x) approaches 5. As x approaches 9 from the left, f(x) approaches 4. O As x approaches 9, f(x) approaches 5, but f(9) = 4. In this situation is it possible that lim f(x) exists? Explain. X - 9 O Yes, f(x) could have a hole at (9, 5) and be defined such that f(9) = 4. Yes, f(x) could have a hole at (9, 4) and be defined such that f(9) = 5. Yes, if f(x) has a vertical asymptote at x = 9, it can be defined such that lim f(x) = 5, lim f(x) = 4, and lim f(x) exists. x - 9- x _ g+ x - 9 No, lim f(x) cannot exist if lim f(x) * lim f(x). x - 9 x- 9- x - 9+