Explore whether variation in Weight can explain variation in Pulse1 using the data pulse.xisx 1) Looking at the scatterplot, there is a [ Select ] between weight and pulse1 2) The estimated intercept is [ Select ] 3) The residual scatterplot shows no pattern confirming [ Select ] 4) Testing the slope against a Null Hypothesis of 0 gives a P-Value of | Select V so we conclude [ Select ] [select ] Reject the Null and Accept in1 eject the Null and Acce evel of sign 5) As the R2 valu. I to reject the Nut ot appropriatexplore whether variation in Weight can explain variation in Pulse1 using the data pulse.xisx 1) Looking at the scatterplot, there is a [ Select ] between weight and pulse1 strong negative weak positive 2) The estimated intercept is [ Select ] weak negati strong positive 3) The residual scatterplot shows no pattern confirming [ Select ] L 4) Testing the slope against a Null Hypothesis of 0 gives a P-Value of [ Select ] so we conclude [ Select ] 5) As the RZ value is | Select , prediction is not appropriateExplore whether variation in Weight can explain variation in Pulse1 using the data pulse.xisx 1) Looking at the scatterplot, there is a [ Select ] between weight and pulse1 2) The estimated intercept is [Select ] 3) The residual scatterplot shows no pattern confirming { Select ) 4) Testing the slope against a Null Hypothesis of 0 gives a P-Value of [ Select ] Select 0.0288 so we conclude [ Select ] 0.0213 0.042/ 5) As the R2 value is [ Select ] V , prediction is not appropriateExplore whether variation in Weight can explain variation in Pulse1 using the data pulse.xisx _ 1) Looking at the scatterplot, there is a [Select ] between weight and pulse 1 2) The estimated intercept is [ Select ] Select] 116.65 -0.21 3) The residual scatterplot sh 86.48 -0.25 Hect ] 4) Testing the slope against a Null Hypothesis of 0 gives a P-Value of [ Select ] so we conclude [ Select ] V 5) As the R2 value is [ Select ] , prediction is not appropriateExplore whether variation in Weight can explain variation in Pulse1 using the data pulse.xisx + 1) Looking at the scatterplot, there is a [ Select ] between weight and pulse1 2) The estimated intercept is Select 3) The residual scatterplot shows no pattern confirming Select ] 4) Testing the slope against a Null Hypothesis of 0 gives a P-Value of [ Select ] so we conclude [ Select ] 5) As the Re value is [ Select ] . prediction is not appropriate Select] 61.598Explore whether variation in Weight can explain variation in Pulse1 using the data pulse xisx 1) Looking at the scatterplot, there is a [ Select ] between weight and pulse1 2) The estimated intercept is [ Select ] 3) The residual scatterplot shows no pattern confirming [ Select ] Select normal distribution for the residuals constant variance 4) Testing the slope against a Null Hypothesis of 0 gives a P-Value of [ Select ] so we conclude _[ Select ] 5) As the R- value is [ Select ] V, prediction is not appropriate