1. Express the confidence interval29.7% 5.9%in interval form.
2. We wish to estimate what percent of adult residents in a certain county are parents. Out of 300 adult residents sampled, 105 had kids. Based on this, construct a 95% confidence interval for the proportion, p, of adult residents who are parents in this county.

< p <

3. Assume that a sample is used to estimate a population proportionp. Find the margin of errorM.E. that corresponds to a sample of size 148 with 74.3% successes at a confidence level of 95%.

M.E. =

4. Giving a test to a group of students, the grades and gender are summarized below

	A	B	C	Total
Male	11	3	8	22
Female	16	20	4	40
Non-binary	9	7	17	33
Total	36	30	29	95

Letrepresent the percentage of all non-binary students who would receive a grade of C on this test. Use a 90% confidence interval to estimate p to three decimal places.

5. You want to obtain a sample to estimate a population proportion. At this point in time, you have no reasonable estimate for the population proportion. You would like to be 99.9% confident that you estimate is within 3% of the true population proportion. How large of a sample size is required?

n =

6. If n=560 andp(p-hat) =0.31, find the margin of error at a 99% confidence level

Give your answer to three decimals

7. You want to obtain a sample to estimate a population proportion. Based on previous evidence, you believe the population proportion is approximatelyp=12% You would like to be 98% confident that your estimate is within 2% of the true population proportion. How large of a sample size is required?

n =

8. Express the confidence interval (65%,76%) in the form of p^ME.

9. Express the confidence interval 38.9%