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Express x = 12.8 as a double-precision IEEE float fl(x), using the round-to-nearest rule.Compute the relative error d = |x fl(x)|/|x| exactly as a base-10
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Express x = 12.8 as a double-precision IEEE float fl(x), using the round-to-nearest rule.Compute the relative error d = |x fl(x)|/|x|
exactly as a base-10 number, and show that d satisfies the upper bound d < = epsilon_mach / 2
Express x = 12.8 as a double-precision IEEE float fl(x), using the round-to-nearest rule.Compute the relative error d = |x fl(x)|/|x|
exactly as a base-10 number, and show that d satisfies the upper bound d < = epsilon_mach / 2
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