External reactions\ FBD\ From the FBD for the entire truss structure, the equilibrium equations can be written as\

\\\\Sigma F_(x)=0->A_(x)=0\ \\\\Sigma F_(y)=0->Ay+H_(y)=80\\\\times 2+100\ \\\\Sigma M_(H)=0->30\\\\times 80+20\\\\times 80+10\\\\times 100=40\\\\times A_(y--(2))

\ Solving eqns. (1&2),\ (a) The vertical reaction at

A

is

Ay=125

(kip)\ (b) The vertical reaction at

H

is

H_(y)=135

(kip)\ Using the FBD/equilibrium for an appropriate cut section, the internal axial force in member CE is given as\ (kip)

External reactions FBD From the FBD for the entire truss structure, the equilibrium equations can be written as Fx=0Ax=0Fy=0Ay+Hy=802+100(1)MH=03080+2080+10100=40Ay(2)(2) Solving eqns. (1\&2), (a) The vertical reaction at A is Ay=125 (kip) (b) The vertical reaction at H is Hy=135 (kip) Using the FBD/equilibrium for an appropriate cut section, the internal axial force in member CE is given as (kip)