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Extra On ad Final ELL M160 F Final Else 12 Mathwa 2o mylab.pearson.com/Student/PlayerTest.aspx?canvas_workflow_state=available& canvas_enrollment_state= acti... > C ring 2024-MKim Angel Gieng This test: 150 inal

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Extra On ad Final ELL M160 F Final Else 12 Mathwa 2o mylab.pearson.com/Student/PlayerTest.aspx?canvas_workflow_state=available& canvas_enrollment_state= acti... > C ring 2024-MKim Angel Gieng This test: 150 inal Exam point(s) possible This question: 5 Submit test point(s) possible list K Groups of adults are randomly selected and arranged in groups of three. x P(x) = The random variable x is the number in the group who say that they 0 0 368 would feel comfortable in a self-driving vehicle. Determine whether a n 19 probability distribution is given. If a probability distribution is given, find its 1 0 427 mean and standard deviation. If a probability distribution is not given. 2 0.183 identify the requirements that are not satisfied. 3 0.022 n 20 Does the table show a probability distribution? Select all that apply 121 A. Yes, the table shows a probability distribution. B. No, the random variable x is categorical instead of numerical 122 C. No, the random variable x's number values are not associated with probabilities D. No, not every probability is between 0 and 1 inclusive 1 23 E. No, the sum of all the probabilities is not equal to 1. Find the mean of the random variable x. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. 124 O A. H= adult(s) (Round to one decimal place as needed. 25 OB. The table does not show a probability distribution. Find the standard deviation of the random variable x. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. 26 O A. 6= adult(s) (Round to one decimal place as needed Nor B. The table does not show a probability distribution. 127 J 1 28 9.6K Norm 29 All Time Remaining: 02 10:13 Next e here to searchExtra Credit x ) Final Exam X K M160 FINAL EXA X Final Exam x XMathway | Alget x + son.com/Student/PlayerTest.aspx?canvas_workflow_state= available&canvas_enrollment_state=active&canvas_user_id=6846208canvas_modul... C Angel Gieng Question 26 of 30 This test: 150 point(s) possible This question: 5 point(s) possible Submit test K Use the accompanying radiation levels |in ka W for 50 different cell phones 0.20 0.21 0.33 0.47 0.62 0.63 0.64 0.65 0.80 0.85 - 0.88 0.88 0.90 0.90 0 91 0.92 0.94 1.00 1.04 1.11 Find the percentile Poo 1.11 1.12 1.13 1.14 1 15 1.15 1.17 1.18 1.18 1.19 1 23 1 23 1.23 1.23 1.24 1.26 1.26 1 28 1.29 1.30 1.34 1.35 1.40 1.42 1.44 1.45 1.47 1.50 1.51 1.53 Poo =kq (Type an integer or decimal rounded to two decimal places as needed.) Time Remaining: 02:10:02 Nexter Extra Credit Final Exam X - M160 FINAL EXA x P Final Exam x INMathway | Algeb b.pearson.com/Student/PlayerTest.aspx?canvas_workflow_state=available&canvas_enrollment_state=active8canvas_user_id=6846208 canvas_modul... * MKim Angel Gieng Question 27 of 30 This test: 150 point(s) possible This question: 5 point(s) possible Submit tes K The overhead reach distances of adult females are normally distributed with a mean of 197.5 cm and a standard deviation of 8.3 cm. a. Find the probability that an individual distance is greater than 207.50 cm. b. Find the probability that the mean for 25 randomly selected distances is greater than 196.20 cm. c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30? a. The probability is 'Round to four decimal places as needed.) b. The probability is (Round to four decimal places as needed.) c. Choose the correct answer below O A. The normal distribution can be used because the finite population correction factor is small O B. The normal distribution can be used because the mean is large. C. The normal distribution can be used because the probability is less than 0.5 D. The normal distribution can be used because the original population has a normal distribution. Time Remaining: 02:09:57 Next /Player,aspx? cultureld=&theme=math&s.. arch AExtra Credit X Final Exam X M160 FINAL EXA X P Final Exam x Do Mathway | Algeb + 0 earson.com/Student/PlayerTest.aspx?canvas_workflow_state=available&canvas_enrollment_state=active&canvas_user_id=6846208 canvas_modul... C im Angel Gieng Question 28 of 30 This test: 150 point(s) possible This question: 5 point(s) possible Submit test The table below describes the smoking habits of a group of asthma sufferers. If one of the 1156 people is randomly selected, find the probability that the K person is a man or a heavy smoker. Round to three decimal places as needed. Occasional Regular Heavy Nonsmoker Smoker Smoker Smoker Total Men 431 50 49 601 Women 382 18 86 39 555 Total 813 157 1156 O A. 0.557 O B. 0.596 O C. 0.511 O D. 0.554 Time Remaining: 02:09:52 Next yer.aspx? cultureld=&theme=math&style=highered&disableStandbyIndicator=true&assignmentHandlesLocale=true&enablelesSession=True&iesClientUri=https%3A%2F%2Flogin.pears...Extra Credit X - Final Exam x M160 FINAL EX X Final Exam x Mathway | Algeb X + O arson.com/Student/PlayerTest.aspx?canvas_workflow_state=available&canvas_enrollment_state=active8canvas_user_id=684620&canvas_modul... > C m Angel Gieng Question 29 of 30 This test: 150 point(s) possible This question: 5 point(s) possible Submit test Rhino viruses typically cause common colds. In a test of the effectiveness of echinacea, 42 of the 47 subjects treated with echinacea developed rhinovirus K infections. In a placebo group, 77 of the 93 subjects developed rhinovirus infections. Use a 0.01 significance level to test the claim that echinacea has an effect on rhinovirus infections. Complete parts (a) through (c) below. a. lest the claim using a nypothesis test. Consider the first sample to be the sample of subjects treated with echinacea and the second sample to be the sample of subjects treated with a placebo. What are the null and alternative hypotheses for the hypothesis test? O A. Ho- P1 - P2 D B. Ho P1 7 P2 O C Ho P1 = P2 H1 : P1 * P2 H1: P1 - P2 HIP1 * P2 OD. Ho P1 - P2 DE. HO PI - P2 OF Ho P1 - P2 H1: P1 > P2 H1: P1

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