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F 18.0 0.50- Small Cylinder stroke is 1 Load = 10 Tons Large Cylinder lifts load 9 2.0 03.00 36 of Line Problems:

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F 18.0" 0.50"- Small Cylinder stroke is 1" Load = 10 Tons Large Cylinder lifts load 9" 2.0" 03.00" 36" of " Line Problems: What does the pressure in the oil need to be to lift 10tons? What is the force at the small cylinder? What is the force, F, at the end of the lever (18" to left of pivot)? (Use an FBD and M = 0) If the stroke at the small cylinder is 1" and there is a 4" line 36" long as well as the large cylinder as shown, how much oil is required (minimum)? Give your answer in in and gallons (231in3 = 1 US Gallon) How many strokes of the small cylinder does it take to raise the large cylinder 9"? (This is only filling the large cylinder) If the jack is operated at 40 stroke/minute, how long does it take to raise the 10 tons? Give your answer in minutes and seconds. . If I want to raise the load in 12 seconds I will need a pump. How many horsepower does it need to be (1 hp = 550lb.ft/sec) and what is its flow rate in gallons/minute (gpm)?

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