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siguiente funciOn marginal I'(t) 13. La integral de la t J(t) = eSi a) = -0.06t2 b) I(t) -O.03t2 c) = 800t -O.03t2 +
siguiente funciOn marginal I'(t) 13. La integral de la t J(t) = eSi a) = -0.06t2 b) I(t) -O.03t2 c) = 800t -O.03t2 + 120 - 0.06t2 + 120 = 800 0.06t cuando
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