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Encontrar la soluci6n de la ecuaci6n diferencial que satisface la condici6n inicial dada (problema con valor inicial). (a) (b) (c) (d) (e) tdx +2rdt
Encontrar la soluci6n de la ecuaci6n diferencial que satisface la condici6n inicial dada (problema con valor inicial). (a) (b) (c) (d) (e) tdx +2rdt = O, x(2) = 1. dt (1 + et) = O, = 7/4. r Inrdt = O, r(l) = 1
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Essentials Of Discrete Mathematics
Authors: David J Hunter
2nd Edition
1449604447, 9781449604448
