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f p(x | y=0) = 0.01 and p(x | y=1)= 0.03 and p(y=1) = p(y=0) = 0.5, then p(y=1 | x) = 0.75.
f p(x | y=0) = 0.01 and p(x | y=1)= 0.03 and p(y=1) = p(y=0) = 0.5,
then p(y=1 | x) = 0.75.
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College Algebra And Trigonometry A Unit Circle Approach,
Authors: Mark Dugopolski
6th Edition
0321867564, 9780321867568
