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| f t' . . . . . n orma Ion A team of researchers wants to know If the bait used In the trap
| f t' . . . . . n orma Ion A team of researchers wants to know If the bait used In the trap (scent, sugar or a chemical) Influences the number of (3:5)\" spruce moths that are caught in the trap. The researchers used 60 traps (all the same brand) and randomly assigned them to a different bait. Use the Minitab output provided to answer the following questions. QUESt'O\" 1 Is this an observational study or experiment? Explain in context. Not yet answered Marked out of 1 A v B I 55 35 0 5:5 2| 2.00 F Flag question QUESt'O\" 2 What is the response variable? Not yet answered Select one: Marked out of O a Moths 1.00 ' O b. Number of moths caught F Flag question 0 C. Bait type 0 d. Brand of trap Question 3 Not yet answered Marked out of 1.00 F Flag question Question 4 Not yet answered Marked out of 0.50 F Flag question Question 5 Not yet answered Marked out of 1.50 V Flag question What is the explanatory variable? Select one: Q a. Moths O b. Number of moths caught 0 c. Bait type 0 d. Brand of trap How many levels does the explanatory variable have? Answer: What are the levels of the explanatory variable? IAVBI : z , o s\" 5' Question 6 Not yet answered Marked out of 200 V Flag question Question 7 Not yet answered Marked out of 200 V Flag question State the appropriate hypotheses (Ho and Ha). lullAlelIl sE EH'b'TS lml // Which of the following is the correct definition of the parameter u1 '.7 Select one: 0 a. Where u1 represents the mean number of spruce moths caught on one of the traps, for this population model of moths. O b. Where u1 represents the mean number of spruce moths caught if the trap had a scent, for this population model of moths. 0 ct Where 111 represents the mean number of spruce moths caught if the trap was scented, sugar or chemical, for this population model of moths. 0 d. Where 111 represents the mean number of spruce moths caught in scent traps, for the moths caught. Method Null hypothesis All means are equal Alternative hypothesis Not all means are equal Significance level a = 0.05 Equal variances were assumed for the analysis. Factor Information Factor Levels Values Factor 3 Scent, Sugar, Chemical Analysis of Variance Source DF Adj SS Adj MS F-Value P-Value Factor 2 113.0 56.52 0.63 0.537 Error 57 5130. 90.00 Total 59 5243.0 Model Summary S R-sq R-sq(adj) R-sq(pred) 9.48679 2.169 0.00% 0.00% Means Factor N Mean StDev 95% CI cen 0 24.75 10.29 (20.50, 29.00) Sugar 20 27.80 9.06 (23.55, 32.05) Chemical 20 27.50 9.06 (23.25, 31.75) Pooled StDev = 9.48679 Residual Plots for Scent, Sugar, ... Normal Probability Plot Versus Fits 99.9 201 . .. 8 8 Residual w. ..... . Percent ..... .09 010 0 ...... . 10 -30 15 15 30 25 26 27 28 Residual Fitted Value Histogram 10.0 7.5 Frequency 5.0 2.5 0.0 -8 o 16 ResidualBoxplot of Scent, Sugar, Chemical Boxplot of Scent, Sugar, Chemical 45 40 35 30 Data 25 20 15 10 Scent Sugar Chemical
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