Values for the figure are given in the following table. Note the figure may not be to scale. Value 45 lb 20 lb 115 lb Variable F F F3 a. Write each vector in Cartensian Vector Notation. Round your final answers to 3 significant digits/figures. F F3 11 II ('00 ('00 + lb ('M lb lb K //////// 13 5 10 5 3 12 4 F3 F AF force of 2020 N is applied to a pin. ( 02 0 30 degrees 75 degrees 0 Values for the figure are given in the following table. Note the figure may not be to scale. Variable Value 0 Using the law of sines and/or cosines, F V a. Resolve the force F into components acting along the u and v axes to determine the magnitudes of the components F and F. Round your final answers to 3 significant digits/figures. Three forces are applied to a hook. F2 F2 F3 0 03 5 13 12 y 9730 N 4390 N 2810 N 5 degrees 20 degrees 0 03 F F3 Values for the figure are given in the following table. Note the figure may not be to scale. Variable Value F X a. Write each force (F,F2, F3) as cartesian vectors. b. Find the magnitude of the resultant force FR c. Determine the direction of the resultant force FR, 0 measured counter-clockwise from the positive x-axis in degrees. Answer must be between 0 0 90 d. In which quadrant is FR located? Round your final answers to 3 significant digits/figures. F = F=( F = ( FR = ( 0=( third second fourth + O first 2 + 2 + N In which quadrant is FR located? degrees = N N N Three forces are applied to a hook. y /////////// 13 F2 F3 5 5 4 3 12 F F3 F X Values for the figure are given in the following table. Note the figure may not be to scale. Variable Value F 20 lb 20 lb 120 lb a. Find the magnitude of the resultant force FR b. Determine the direction of the resultant force FR, 0 measured clockwise from the positive x-axis in degrees. Answer must be between 0 0 90 Round your final answers to 3 significant digits/figures. FR = ( ) lb 0 = degrees In which quadrant is FR located? first O second O fourth O third = A bent tube is attached to a wall with brackets as shown. . A force of F = 190 lb is applied to the end of the tube with direction indicated by the dimensions in the figure. a.) Determine the force vector Fin Cartesian components. b.) Resolve the force vector F into vector components parallel and perpendicular to the position vector IDA. Express each of these vectors in Cartesian components. 2013 Michael Swanbom cc) + O BY NC SA x M < B 9 FK kaz 6 A Values for dimensions on the figure are given in the table below. Note the figure may not be to scale. Be sure to align your cartesian unit vectors with the coordinate axes shown in the figure. Values for dimensions on the figure are given in the table below. Note the figure may not be to scale. Be sure to align your cartesian unit vectors with the coordinate axes shown in the figure. Variable Value 9 in 18 in 17 in 55 in 36 in 43 in a. a b C d h g = b. F||DA = FLDA= + ~. + + 3+ + 3+ k) lb k) lb and k) lb Two forces are applied to a hook. X F2 0 0 3 03 04 F 5 4 0 ZA 0 03 Values for the figure are given in the following table. Note the figure may not be to scale. Variable Value F 150 N 480 N 20 degrees 35 degrees 35 degrees 15 degrees 047 F a. Write each force (F,F2) as cartesian vectors. b. Find the resultant force FR, express as a cartesian vector c. Find the magnitude of the resultant force FR d. Determine the coordinate direction angles of the resultant force FR i. a ii. B iii. Y Round your final answers to 3 significant digits/figures. F = ( F = ( FR = ( FR = ( = B = ( Y = ('2 + 2 + 2 + N degrees degrees degrees 5+ j+ k) N k)) N k)) N Three forces are applied to a hook. Force F3 has coordinate direction angles of a = 110 , B = 35 , and Y = 10 . X Variable F Z F F3 0 0 F 5 F3 3 Values for the figure are given in the following table. Note the figure may not be to scale. Value 1000 lb 700 lb 700 lb 15 degrees F a. Write each force (F,F2, F3) as cartesian vectors. b. Find the resultant force FR, express as a cartesian vector c. Find the magnitude of the resultant force FR d. Determine the coordinate direction angles of the resultant force FR i. a ii. iii. Y Round your final answers to 3 significant digits/figures. F = ( F=1 TE F3 = ( FR = ( FR = ( = ( B = Y = ( 2 + 2.) 2 + 2 + + lb degrees degrees degrees j+ + 5+ k) lb k)) lb k)) lb k)) lb The magnitude of the resultant force FR on the hook is known to be 445 N. The magnitude and direction of F is unknown. 1 y 0 F F3 5 13 12 0 F3 F FR F2 X Values for the figure are given in the following table. Note the figure may not be to scale. Variable Value FR 445 N 0 25 degrees 150 N 210 N a. Find the magnitude of the unknown force F b. Determine the direction of the unknown force F, measured clockwise from the positive y-axis in degrees. Answer must be between 0 0 90 Round your final answers to 3 significant digits/figures. F = 0 = N degrees The force vector F has a magnitude of F = 375 lb and acts at point A at an angle = 12.3 with respect to vertical as shown. The force F is balanced by the tension forces parallel to the two rods AC and AB such that the vector equation F + FAC+ FAB = 0 is satisfied. Determine the tension forces in the two rods in Cartesian components. b cc iO BY NC SA 2013 Michael Swanbom NF Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value 4.2 ft 2.2 ft 3.9 ft For the component notation, use an 'xy' coordinate system with 'y' poining up and 'x' pointing to the right. a b C FAC= FAB = + a 2 + 0 3) lb 3) lb