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f7) 1 (+ 1/3 - +2/3 ) dt 8) ,12x - 4/dx 9) So (1 + sin x) dx J_n/6(sec2x) dx 11) _(4 sec 0

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\f7) 1 (+ 1/3 - +2/3 ) dt 8) ,12x - 4/dx 9) So (1 + sin x) dx J_n/6(sec2x) dx 11) _(4 sec 0 tan () de 12) What is the exact area of the region between y = x-x and the x-axis , over the interval [0, 1]

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