F=8,000 lb 18 in. 6 in. X Part A This structural connection is subjected to the 8,000-lb force. Replace this force by an equivalent force and couple acting at the center of the bolt group, O. O F = (-6400i - 4800j) lb, M = -4k kip - ft F F= (-6400i-4800j) (-6400i - 4800j) lb, M = (-3.20i - 7.20j) kip - ft F F= (6400i +4800j) lb, M = (-3.20i +7.20j) kip - ft F= (6400i+4800j) lb, M = 4k kip - ft Submit Request Answer