\fA pool of the shape of an inverted truncated pyramid as shown in the l"ollo1.:I.'ingr gure is lled with water up to 3 meters deep. The top of the pool is a square of side-length l meters, the bottom of the pool is a square of sidelength 2 maters, and the depth of the pool is 4 meters. The area of a horizontal layer of tvaterx meters under the top of the pool is A(x} = (ID 235);5 m2. See this gure. Assume the densityr of water is p lnnfm3, and let the gravity of acceleration he 3 mfsecz. The work, in Ioules, needed to pump all the water in the tank to a nozzle 1 meter above the top of the tank is calculated by the integral 0 3' pg [04(10 2.102(1 + $)d:;n O 1\" pg [300 2.102(1 + $)d:;n O C} pg [04(10 2:32 (5 $)d$ 0 d} pg ff 3(10 2:3)2ds: O a} pg [300 2.102(1 + $)d:;n 0 pg [14(10 22:)2 (2 + $)d$