\fA tourist drops a stone o a cliff and it falls into an ocean. Let s{t} represent the position of the stone {in feet above sea level} tseconds after it was dropped. Explain what the equations s{11} = l] and s'{1'l} = 352 mean in practical terms. Choose the correct answer below. @I A. Eleven seconds alter the stone is dropped. it is 352 feet above the ocean. O B. The stone is dropped from the height of 11 feet and its velocity is 352 this when it hits the ocean. O C. Eleven seconds after the stone is dropped, it hits the ocean and its velocity is 352 his. 0 D. The stone is dropped from a cliff 352 feet high and its velocity is 11 ftfs