Fast Food: A fast-food restaurant estimates that the mean sodium content in one of its breakfast sandwiches is no more than 920 milligrams. A random sample of 44 breakfast sandwiches has a mean sodium content of 925 milligrams. Assume the population standard deviation is 18 milligrams. At = 0.10, do you have enough evidence to reject the restaurant's claim?

n = 44(sample size

x = 925 mg (sample mean)

= 18mg (population standard deviation)

=920

= 0.10

Ho: = 920

Ha: > 920

We know the true population standard deviation will conduct one sample z test.

Test statistic z = (-) //

z = 925 - 920 / 18/

44 = z= 1.84

right-tail test = p(z > 1.84) =1-p (z<

<1.84) = 1 - 0.9671 = 0.0329

p-value = 0.0329 = 0.0329<

<0.10 = p value<

<2

Since the p-value is less than 0.10 significance level, we reject null hypothesis H0 which is ( 920)

The claim of the food restaurant is false.The true mean sodium content in breakfast sandwiches is more than 920 milligrams.