Fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean = 27.3 kilograms and standard deviation = 3.8 kilograms. Let x be the weight of a fawn in kilograms.

Convert the following x intervals to z intervals. (Round your answers to two decimal places.)

(a) x< 30

z<

(b) 19 < x < z

c) 32 < x < 35 < z < Convert the following z intervals to x intervals. (Round your answers to one decimal place.) (d) 2.17 < z < x

(e) z < 1.28 x <

(f) 1.99 < z < 1.44 < x < (g) If a fawn weighs 14 kilograms, would you say it is an unusually small animal? Explain using z values and the figure above.

Yes. This weight is 3.50 standard deviations below the mean; 14 kg is an unusually low weight for a fawn.

Yes. This weight is 1.75 standard deviations below the mean; 14 kg is an unusually low weight for a fawn.

No. This weight is 3.50 standard deviations below the mean; 14 kg is a normal weight for a fawn.

No. This weight is 3.50 standard deviations above the mean; 14 kg is an unusually high weight for a fawn.

No. This weight is 1.75 standard deviations above the mean; 14 kg is an unusually high weight for a fawn.

(h) If a fawn is unusually large, would you say that the z value for the weight of the fawn will be close to 0, 2, or 3? Explain.

It would have a negative z, such as 2.

It would have a z of 0.

It would have a large positive z, such as 3.