Fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean=29.9kilograms and standard deviation=4.7kilograms. Letxbe the weight of a fawn in kilograms.For parts (a), (b), and (c), convert thexintervals tozintervals. (For each answer, enter a number. Round your answers to two decimal places.)

(a

x<30 z< (b

19<x(Fill in the blank. A blank is represented by _____.) _____<z (c)

32<x<35 (fill in the blanks. a blank is represented by _____. there are two answer blanks.) _____<z<_____ first blank second blank

For parts (d), (e), and (f), convert thezintervals toxintervals. (For each answer, enter a number. Round your answers to one decimal place.)(d)

2.17<z(Fill in the blank. A blank is represented by _____.) _____<x (e)

z<1.28 x< (f)

1.99<z<1.44 (Fill in the blanks. A blank is represented by _____. There are two answer blanks.) _____<x<_____ first blank second blank (g)

If a fawn weighs 14 kilograms, would you say it is an unusually small animal?

usingzvalues and the figure above.

Yes. This weight is 3.38 standard deviations below the mean; 14 kg is an unusually low weight for a fawn.

Yes. This weight is 1.69 standard deviations below the mean; 14 kg is an unusually low weight for a fawn. No. This weight is 3.38 standard deviations below the mean; 14 kg is a normal weight for a fawn.

No. This weight is 3.38 standard deviations above the mean; 14 kg is an unusually high weight for a fawn.

No. This weight is 1.69 standard deviations above the mean; 14 kg is an unusually high weight for a fawn.

(h)

If a fawn is unusually large, would you say that thezvalue for the weight of the fawn will be close to 0,2, or 3?

Explain.

It would have a negativez, such as2.

It would have a large positivez, such as 3.

It would have azof 0.