Fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean=27.2kilograms and standard deviation=3.7kilograms. Letxbe the weight of a fawn in kilograms.For parts (a), (b), and (c), convert thexintervals tozintervals. (For each answer, enter a number. Round your answers to two decimal places.)

(a)x<30

z<

(b)19<x(Fill in the blank. A blank is represented by _____.)

_____<z

(c)32<x<35 (Fill in the blanks. A blank is represented by _____. There are two answer blanks.)

_____<z<_____

first blank

second blank

For parts (d), (e), and (f), convert thezintervals toxintervals. (For each answer, enter a number. Round your answers to one decimal place.)

(d)2.17<z(Fill in the blank. A blank is represented by _____.)

_____<x

(e)z<1.28

x<

(f)1.99<z<1.44 (Fill in the blanks. A blank is represented by _____. There are two answer blanks.)

_____<x<_____

first blank

second blank

(g)If a fawn weighs 14 kilograms, would you say it is an unusually small animal? Explain usingzvalues and the figure above.

Yes. This weight is 3.57 standard deviations below the mean; 14 kg is an unusually low weight for a fawn.

Yes. This weight is 1.78 standard deviations below the mean; 14 kg is an unusually low weight for a fawn.

No. This weight is 3.57 standard deviations below the mean; 14 kg is a normal weight for a fawn.

No. This weight is 3.57 standard deviations above the mean; 14 kg is an unusually high weight for a fawn.

No. This weight is 1.78 standard deviations above the mean; 14 kg is an unusually high weight for a fawn.

(h)If a fawn is unusually large, would you say that thezvalue for the weight of the fawn will be close to 0,2, or 3? Explain.

It would have azof 0.

It would have a large positivez, such as 3.

It would have a negativez, such as2.