Fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean=29.7kilograms and standard deviation=4.5kilograms. Letxbe the weight of a fawn in kilograms.For parts (a), (b), and (c), convert thexintervals tozintervals. (For each answer, enter a number. Round your answers to two decimal places.)(a) x<30 z< (b) 19<x(Fill in the blank. A blank is represented by _____.) _____<z (c) 32<x<35 (fill in the blanks. a blank is represented by _____. there are two answer blanks.) _____<z<_____ first blank second for parts (d), (e), and (f), convert thezintervals toxintervals. (For each answer, enter a number. Round your answers to one decimal place.)(d) 2.17<z(Fill in the blank. A blank is represented by _____.) _____<x (e) z<1.28 x< (f) 1.99<z<1.44 (Fill in the blanks. A blank is represented by _____. There are two answer blanks.) _____<x<_____ first blank second (g) if a fawn weighs 14 kilograms, would you say it is an unusually small animal? explain usingzvalues and the figure above.Yes. This weight is 3.49 standard deviations below the mean; 14 kg is an unusually low weight for a fawn.Yes. This weight is 1.74 standard deviations below the mean; 14 kg is an unusually low weight for a fawn. No. This weight is 3.49 standard deviations below the mean; 14 kg is a normal weight for a fawn.No. This weight is 3.49 standard deviations above the mean; 14 kg is an unusually high weight for a fawn.No. This weight is 1.74 standard deviations above the mean; 14 kg is an unusually high weight for a fawn. (h) If a fawn is unusually large, would you say that thezvalue for the weight of the fawn will be close to 0,2, or 3? Explain.It would have a large positivez, such as 3.It would have azof 0. It would have a negativez, such as2.