Fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean=29.7kilograms and standard deviation=3.2kilograms. Letxbe the weight of a fawn in kilograms.For parts (a), (b), and (c), convert thexintervals tozintervals. (For each answer, enter a number. Round your answers to two decimal places.)(a)

x<30 z< (b)

19<x(Fill in the blank. A blank is represented by _____.) _____<z (c)

32<x<35 (fill in the blanks. a blank is represented by _____. there are two answer blanks.) _____<z<_____ first blank second blank

For parts (d), (e), and (f), convert thezintervals toxintervals. (For each answer, enter a number. Round your answers to one decimal place.)(d)

2.17<z(Fill in the blank. A blank is represented by _____.) _____<x (e)

z<1.28 x< (f)

1.99<z<1.44 (Fill in the blanks. A blank is represented by _____. There are two answer blanks.) _____<x<_____ first blank second blank (g)

If a fawn weighs 14 kilograms, would you say it is an unusually small animal? Explain usingzvalues and the figure above. Yes. This weight is 4.91 standard deviations below the mean; 14 kg is an unusually low weight for a fawn.Yes. This weight is 2.45 standard deviations below the mean; 14 kg is an unusually low weight for a fawn. No. This weight is 4.91 standard deviations below the mean; 14 kg is a normal weight for a fawn.No. This weight is 4.91 standard deviations above the mean; 14 kg is an unusually high weight for a fawn.No. This weight is 2.45 standard deviations above the mean; 14 kg is an unusually high weight for a fawn.

(h)

If a fawn is unusually large, would you say that thezvalue for the weight of the fawn will be close to 0,2, or 3? Explain. It would have azof 0.It would have a negativez, such as2. It would have a large positivez, such as 3.