\fDaily counts = fyily 21 ..- yng n= 365. a there are M number of frogs in the pond. Pityis) probability of seeing a frogaday - . To Assumptions : the number of frogs seen each day is independent of the previous day number The probability of seeing a frog each each day is the same for 365 days: There are only two possible outcomes ( feeing a frog or not seeing a frog !) b) Likelihood L( O,M) = M OF (1 - 0 ) M - TC - TT ( M) ET (1 - 0)M - ZY " Taking the Log of Likelihood 6 2 ( AM) =/ log ) + ti logo + nM - dog (-0) = ZYi - ( nM - Z Y C ) 1 - 0 Equating to zero ( MM - Zti ) 1- 0 (nM - Epi ) 9 = Etc ( 1 - 3) nMe = Zy MLE ON = ETC nM nM