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fFind the points at which the graph of the equation has a vertical or horizontal tangent line. 16X2+y232X+8y+16=0 horizontal tangents (X, y) = ( (smaller
\fFind the points at which the graph of the equation has a vertical or horizontal tangent line. 16X2+y232X+8y+16=0 horizontal tangents (X, y) = ( (smaller y-value) X (X: Y) = (smaller X-value) X (X: Y) = (larger Xvalue) MU ) ) (larger yvalue) ) ) vertical tangents (X: Y) = ( X Use the function f and the given real number a to find (f-1)'(a). DNE.) f(x) = X'+7x- 1, a = -9 (f - 1 ) ' ( - 9) = X
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