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maintors, 2 DMM's, DC power supply, 1.5 V battery and connec- Romans]: data in the appropriate places in the given data tables with their digital
maintors, 2 DMM's, DC power supply, 1.5 V battery and connec- Romans]: data in the appropriate places in the given data tables with their digital voltmeter gives a positive (+) reading if the (+) lead is of \"high\" potential and the "common\" lead to the point of connection is reversed, the reading is negative (). 5 ammeter gives a positive (+) reading if the current enters 1Head and leaves from the \"common\" lead. If the connection and measure the resistances of the individual resistors. data tables. a in gure (6.1) with the polarities of the power supply and This should be done with the power supply off. poladties shown in the circuit diagram. all e numbers. it and the battery from the circuit. 5, 76 V 1.64 0.02102 0.0041 + VB + B Ls I1 A 13 LB C 12 I1 0 . 0 161 R1 Loop (1) R2 Loop (2) R3 194 52 376-12 lian + 12 13 I1 L2 13 G1 G2 G3 Figure (6.1): Two loop circuit with two emfs Right Left WCA V. ANALYSIS: Procedure (1): Two Loop Circuit 1. Verify KLR for each loop by summing the voltages around each loop. Voltage rises juan should count positive (+) and voltage drops should count negative (-). nce 2. If the EV around any of the loops is not zero, find the percent difference between the sum of the voltage rises and the sum of the voltage drops. 3. Verify KJR for junction A by summing the currents entering the junction and the currents leaving the junction. Find the percent difference between these two values. 4. What about the outer (larger) loop? Is KLR satisfied around the big loop within the accuracy of the experiment? 5. Calculate the power provided to the circuit by the power supply. Call this Pprovided. 6. Calculate the power dissipated by the three resistors. This is the rate of electrical energy conversion to heat. Call this Pdissipated- 7. Calculate the power input into the battery. This is the rate of electrical energy con- version to chemical energy. The battery is being "charged" by the energy input into it. Call this Pbattery. 8. From the principle of conservation of energy we expect that Pprovided = Pdissipated + Pbattery (1) 9. Verify energy conservation by calculating the percent difference between Pprovided and the sum of (Pdissipated + Pbattery).
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