\fHints for the maximum and minimum values of f (:13): The maximum value of y : sin (at) is y : 1 and the corresponding :1: values are a: : g and multiples of 2 a" less than and more than this x value. You may want to solve % (m 2) : g. The minimum value of y : sin (3:) is y : 1 and the corresponding :13 values are :1: : 3 7: and 7 multiples of 2 71' less than and more than this :13 value. You may want to solve % (a: 2) : 37. If you get a value for a: that is less than 0, you could add multiples of P to get into the next cycles. If you get a value for a: that is more than P, you could subtract multiples of P to get into the previous cycles. For a: in the interval [0, P]. the maximum y-value and corresponding arr-value is at: la! 7r si11[a'] :E 0 .5] a? t V'- Iai w sinta) 1t 0