\fHistory Bookmarks Profiles Tab Window Help O pal Pearsc X Assign x Do Ho X *Course x New T X + C mylab.pearson.com/Student/PlayerHomew... 0 Paused TP 231 2022 Spring B 20713 Tran (1) Homework: HW 20: HW Score: Ch 10 - Least Question 4, 12.5%, 2 of 16 Squares Regression 10.2.5 points Line O Points: 0 of Save Arm circumferences (cm) and heights (cm) are measured from randomly selected adult females. The 136 pairs of measurements yield x = 32.88 cm, y = 163.16 cm, r= 0.055, P-value = 0.525, and y = 158 + 0.1703x. Find the best predicted value of y (height) given an adult female with an arm circumference of 36.0 cm. Let the predictor variable x be arm circumference and the response variable y be height. Use a 0.05 significance level. The best predicted value is cm. (Round to two decimal places as needed. Get more help - Clear all Check answer APR 27\fChrome File Edit View History Bookmarks Profiles Tab Window Help 00 su Pearsc X Assign X Do Ho X Cours X New T x + mylab.pearson.com/Student/PlayerHomew... ( 7 Paused STP 231 2022 Spring B 20713 Tran (1) Homework: HW 20: HW Score: O Ch 10 - Least Question 6, 12.5%, 2 of 16 10.2.11 Squares Regression points Part 1 of 3 Points: 0 of Save Line Next question a. Using the pairs of values for all 10 points, find the equation of the regression line. b. After removing the point with coordinates (2,4), use the pairs of values for the 10-0 remaining 9 points and find the equation of the regression line. c. Compare the results from parts (a) and (b). 8 10 a. What is the equation of the regression line for all 10 points? y =+x (Round to three decimal places as needed.) Get more help - Clear all Check answer APR 27 C..\fAN Pearson Access x _Assignments Do Homework - HW 20: Ch 10 x * Course Hero New Tab x + -> C a mylab.pearson.com/Student/PlayerHomework.aspx?homeworkld=622871014&questionid=1&flushed=false&cld=6914052¢erwin=yes * Paused STP 231 2022 Spring B 20713 Tran (1) Maryana Tymkiv 04/27/22 6:28 PM Homework: HW 20: Ch 10 - Least Squares Question 8, 10.2.20 HW Score: 12.5%, 2 of 16 points Regression Line Part 1 of 2 Points: 0 of 1 Save The data show systolic and diastolic blood pressure of certain people. Find the regression equation, letting the systolic reading be the independent (x) variable. If one of these people has a systolic blood pressure of 113 mm Hg, what is the best predicted diastolic blood pressure? Systolic 150 129 142 112 134 126 120 Diastolic 122 88 96 106 80 98 63 95 64 Click the icon to view the critical values of the Pearson correlation coefficient r. X Critical Values of the Pearson Correlation Coefficient r What is the regression equation? ( = 0.05 a = 0.01 0.950 0.990 y =+x (Round to two decimal places as needed.) 0.878 0.959 0.811 0.917 0.754 0.875 0.707 0.834 0.666 0.798 0.632 0.765 0.602 0.735 0.576 0.708 0.553 0.684 0.532 0.661 0.514 0.641 0.497 0.623 0.606 0.468 0.590 0.456 0.575 0.444 0.561 0.396 0.505 0.361 0.463 0.335 0.430 0.312 0.402 45 0.294 0.378 50 0.279 0.361 60 0.254 0.330 70 0.236 0.305 80 0.220 0.286 90 0.207 0.269 Help me solve this View an example Get more help - Check answer MacBook Air