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Fiefer to this data table: Specific heat of Molar heat of fusion of ice =6.01kl/mol ice=203skCsteam=1.99JgC.Water=4.184dgC Molarheatofvaporizationofwater=40.79kdmole. Caiculate the heat in kJ required to transform

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Fiefer to this data table: Specific heat of Molar heat of fusion of ice =6.01kl/mol ice=203skCsteam=1.99JgC.Water=4.184dgC Molarheatofvaporizationofwater=40.79kdmole. Caiculate the heat in kJ required to transform 433 grams of ice at - 70.0 degrees C to liquid water at 50.0 degrees C. 26.7kJ3.28kJ8.93kJ297kJ5.04kJ9.53101kJ613kJ1.91102kJ Qlear myactertion

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