Question
Fifty-eight percent of the fish in a large pond are minnows. Imagine scooping out a simple random sample of 20 fish from the pond and
Fifty-eight percent of the fish in a large pond are minnows. Imagine scooping out a simple random sample of 20 fish from the pond and observing the sample proportion of minnows. What is the standard deviation of the sampling distribution? Determine whether the 10% condition is met.
The standard deviation is 0.1104. The 10% condition is not met because there are less than 200 minnows in the pond. The standard deviation is 0.1104. The 10% condition is met because it is very likely there are more than 200 minnows in the pond. The standard deviation is 0.8896. The 10% condition is met because it is very likely there are more than 200 minnows in the pond. The standard deviation is 0.8896. The 10% condition is not met because there are less than 200 minnows in the pond. We cannot determine the standard deviation because we do not know the sample mean. The 10% condition is met because it is very likely there are more than 200 minnows in the pond.
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