Fifty-four wild bears were anesthetized, and then their weights and chest sizes were measured and listed in a data set. Results are shown in the accompanying display. Is there sufficient evidence to support the claim that there is a linear correlation Correlation Results between the weights of bears and their chest sizes? When measuring an anesthetized bear, is it easier to measure chest size than weight? If so, does it appear that a measured chest size can be used to predict the weight? Use a significance level of Correlation coeff, r: 0.952955 x = 0.05. Critical r: 1 0.2680855 P-value (two tailed): 0.000 Determine the null and alternative hypotheses. Ho: p H1 : P (Type integers or decimals. Do not round.) Identify the correlation coefficient, r. r=(Round to three decimal places as needed.) Identify the critical value(s). (Round to three decimal places as needed.) O A. There are two critical values at r= + O B. There is one critical value at r= ]. Is there sufficient evidence to support the claim that there is a linear correlation between the weights of bears and their chest sizes? Choose the correct answer below and, if necessary, fill in the answer box within your choice. (Round to three decimal places as needed.) O A. No, because the test statistic falls between the critical values. O B. Yes, because the test statistic |falls between the critical values. O C. No, because the absolute value of the test statistic |exceeds the critical value. O D. Yes, because the absolute value of the test statistic exceeds the critical value. O E. The answer cannot be determined from the given information. When measuring an anesthetized bear, is it easier to measure chest size than weight? If so, does it appear that a measured chest size can be used to predict the weight? O A. No, it is easier to measure weight than chest size because the chest is not a flat surface. O B. Yes, it is easier to measure a chest size than a weight because measuring weight would require lifting the bear onto the scale. The chest size could not be used to predict weight because there is not a linear correlation between the two