Figure 3 I have made this circuit by dragging a number of wires: you can see where the connections are when there is a dotted circle. And then I have dragged different circuit elements to makethe complete circuit as shown. Again we always have to look at the conventional direction of the current, not the direction of the flow of electrons. When I close the switch, i see: Open switch Close switch To close switch, click on it. The switch is reading 0 n and the red arrows are in the direction of the conventional current. orientation-) _| I When you click on any circuit element, a yellow box a ppea rs around the element. Here I have clicked on the resistor, you can either \"trash\" it or change its value {value in slide bar). You can also \"cut" a wire by clicking on the connection 0 point. Scissors appear.C|ick on the scissors. Figure 4a Make sure all connections have a blue dotted circle; if circle is red. then connection incorrect. Example series circuit Example parallel circuit 26. Use the same circuit B as in question 24, and now c0mpare L1 in circuit B with LIA in circuit A. You observe a. L1 is more bright than L1A. b. L1 is less bright than LIA. 0. L1 has same brightness as LIA. 27. Your observation in question 26 can be best described as a. LIA and L1 have the same resistance, so no matter how they are connected, they will shine with the same brightness. b. LIA and L1 have the same resistance and the same current and voltage thru them, so they shine with the same brightness. c. LlA will always outshine LI. (1. LIA will always be dimmer than L1. 28. Use the same circuit B as in question 24 (which has L1 and L2 each at 10 Q and battery voltage set at 9 V), conapare the current put out by the battery for circuit A, IA, with the current put out by the battery in circuit B, 13. Your observation may be best described as a. The current IA is the same as 18 because in each circuit A and B, we have a 9 V battery. b. The current IA is smaller than the current IB because the Req in circuit A is larger than the Req of circuit B, for the same voltage source. 0. The current IA is smaller than the current IB because the Req in circuit A is smaller than the Req of circuit B, for the same voltage source. 29. Using the same circuit B as in question 24, you observe the current thru lightbulbs L1, L2 and L3 to be a.Ll>L2>L3 b.L1=L2:L3 c.L1>L2=L3 d.L1