figure to follow:

1. Show a diagram similar to Fig 3.5 for the following sequence of instructions: Assume that register $a0 initially contains +37 and that register $al contains -12. All other registers contain garbage. CHAPTER 3. ASSEMBLY LANGUAGE FOR MIPS $a0=$a1=$a2=$v0=add$v0,$a0,$a1$v0=sub$v0,$v0,$a2$v0= Figure 3.5: Example to calculate 5+1730, leaving the result in register $v0. The contents of the relevant registers are shown in hexadecimal before and after each instruction is executed. - Register \$v0 contains garbage. - It is ok to store a new value in register $ v0; the current value is not needed. We do not assume that register $v0 contains 0 . The add instruction will overwrite any value that is in register \$vo, so its initial contents is irrelevant here. In Fig 3.5 the add instruction will add the contents of register $a0 (5) to the contents of register $a1 (17) and store the result (22) in register \$v0. The sub instruction will subtract the contents of register $a2(30) from the value in register \$v0 (22) and store the result (8) in register $v0