Question
# File: mlIfElse.asm # Author: ************ # Date: mm/dd/yyyy # Purpose: Practice if-else logic #---------------------------------------------- # WRITE MIPS CODE FOR THE FOLLOWING C++ CODE: #include
# File: mlIfElse.asm
# Author: ************
# Date: mm/dd/yyyy
# Purpose: Practice if-else logic
#----------------------------------------------
# WRITE MIPS CODE FOR THE FOLLOWING C++ CODE:
#include
#include
#using namespace std;
#void main()
#{
# //declare variables
# string result;
# int x;
# //prompt for, read in a value for x
# cout << "Please enter a value for x (integer): ";
# cin >> x;
#
# ==========================================================
# //PROBLEM1 - if x has a value of 3 or 4, print "ddd", else print "eee"
# result = "";
# if(x==3 || x==4) result = result + "ddd";
# else result = result + "eee";
# cout << "1.\t" << result << endl;
#
# =============================================================
# //PROBLEM2 - if x is less than 5 and greater than 2,
# // then check to see if it is even. If it is even,
# // print "ddd". If its not even, the original "ccc" is printed.
# // But if x was not less than 5 and greater than 2,
# // print "eee".
# result = "ccc";
# if (x < 5 && x > 2)
# {
# if (x%2 == 0) result = "ddd";
# }
# else result = "eee";
# cout << "2.\t" << result << endl;
#
# ==========================================================
# //PROBLEM3 - if x has a value if 2, print "bbb"
# // if x has a value of 3, print "ccc"
# // if x has a value of 4, print "ddd"
# // if x has a value other than 2, 3, or 4 print "eee"
# result = "";
# switch (x)
# {
# case 2: result = result + "bbb"; break;
# case 3: result = result + "ccc"; break;
# case 4: result = result + "ddd"; break;
# default: result = result + "eee";
# }
# cout << "3.\t" << result << endl;
#
# =========================================================
# //PROBLEM4 - if x has a value of 4, print "ddd"
# // if x has a value of 3, print "ccc"
# // any other value (not 3 or 4), print "eee"
# result = "";
# if (x==4) result = result + "ddd";
# else if (x==3) result = result + "ccc";
# else result = result + "eee";
# cout << "4.\t" << result << endl;
#
# }//end main()
.data
.eqv SYS_PRINT_WORD 1 #word, byte, character
.eqv SYS_PRINT_FLOAT 2 #float
.eqv SYS_PRINT_DOUBLE 3 #double
.eqv SYS_PRINT_TEXT 4 #text (zero terminated)
.eqv SYS_INPUT_WORD 5 #input word
.eqv SYS_EXIT 10 #terminate
# //declare variables
# string result;
# int x;
result: .asciiz "0123456789012345" #max of 16 chars
x: .word 0 # copy of $s5
endl: .asciiz " "
tx_prompt: .asciiz "Please enter a value for x (integer): "
tx_bbb: .asciiz "bbb"
tx_ccc: .asciiz "ccc"
tx_ddd: .asciiz "ddd"
tx_eee: .asciiz "eee"
prob1_label: .asciiz "1.\t"
prob2_label: .asciiz "2.\t"
prob3_label: .asciiz "3.\t"
prob4_label: .asciiz "4.\t"
.text
.globl main
main:
# //prompt for, read in a value for x
# cout << "Please enter a value for x (integer): ";
# cin >> x;
la $a0, tx_prompt # load address of prompt for syscall
li $v0, SYS_PRINT_TEXT # specify Print String service
syscall # print the prompt string
li $v0, SYS_INPUT_WORD # specify Read Integer service
syscall # Read the number. After this instruction, the number read is in $v0.
add $s5, $v0, $zero # transfer the number to s5
la $t0, x
sw $s5, 0($t0) # s5 = x = input word number
la $s4, result # s4 = address of result string
# //PROBLEM1
sb $zero, 0($s4) #result = ""
li $t1, 3 #x==3?
beq $s5, $t1, ddd1 # yes, branch
li $t1, 4 #x== 4?
beq $s5, $t1, ddd1 #yes, branch
fals1: move $a0, $s4 #a0 = &result
la $a1, tx_eee #a1= &tx_eee
jal concatstr #result= result + "eee"
j prt1
ddd1: move $a0, $s4 #a0= &result
la $a1, tx_ddd # a1= &tx_ddd
jal concatstr
prt1: la $a0, prob1_label
li $v0, SYS_PRINT_TEXT
syscall
move $a0, $s4 #print result
li $v0, SYS_PRINT_TEXT
syscall
la $a0, endl
li $v0, SYS_PRINT_TEXT
syscall
# //PROBLEM2
# //PROBLEM3
# //PROBLEM4
#---- terminate ---
exit:
li $v0, SYS_EXIT
syscall
#-------------------------------------------------------------
# concatstr - concatenate $a1 to $a0 string
# input $a0 - address of result string
# input $a1 - address of string to concatenate to result
# output $a0 - address of end of string \0
# output $a1 - address of end of string \0
#-------------------------------------------------------------
concatstr:
#find \0 in a0 result string
findend:
lbu $t0, 0($a0)
beq $t0, $zero, docopy # branch if result.at(a0) == '\0'
addiu $a0, $a0, 1
j findend # move to next char and keep looking
# concatenate a1 chars to a0 chars
docopy:
lbu $t0, 0($a1) # get current char from a1
sb $t0, 0($a0) # copy current char to a0
beq $t0, $zero, concatstr_exit # if char == '\0', branch & stop if char was '\0'
addiu $a0, $a0, 1 # advance to next char
addiu $a1, $a1, 1 # advance to next char
j docopy
concatstr_exit:
jr $ra
#.end main
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