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Fill in the gaps in the function newton _ root _ finder below so that it returns the approximation xn + 1 for a root

Fill in the gaps in the function newton_root_finder below so that it returns the approximation xn+1 for a root of the given function f = f with derivative f= f_prime found using Newton's method with initial approximation x0, using the given = tolerance value applied to both the function error and the approximation change, ie, iteration stops when both of the following are true:
|f(xn+1)|<and|xn+1xn|<
provided that this happens without exceeding the specified maximum number of iterations max_iterations. If the specified maximum number of iterations is exceeded the function should raise a RuntimeError with the message "Max iterations reached without convergence in newton_root_finder".
For example, if the function is tested with the code below:
f = lambda x: x**3+ x +1
f_prime = lambda x: 3* x**2+1
x0=-1
tol =0.5e-3
max_iterations =20
try:
root = newton_root_finder(f, f_prime, x0, tol, max_iterations)
print(f"Root found {root:.6f}(6 dps)")
except RuntimeError as err:
print(err)
the test code should print:
Root found -0.682328(6 dps)

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