Question
Finally, we need to find 1 g ( a ) . We previously determined that g ( a ) = a 2 + 3 a
Finally, we need to find
| 1 |
| g(a) |
.
We previously determined that
g(a) = a2 + 3a.
Therefore, the quotient
| 1 |
| g(a) |
is a fraction with 1 in the numerator and the expression
a2 + 3a
in the denominator, which gives the following result.
| 1 |
| g(a) |
=
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Applied Time Series Analysis With R
Authors: Wayne A Woodward, Henry L Gray, Alan C Elliott
2nd Edition
1498734278, 9781498734271
