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Find an equation for the line tangent to the curve at the point defined by the given value of t. Also, find the value


Find an equation for the line tangent to the curve at the point defined by the given value of t. Also, find the value of d'y dx x = 6 cost, y=6 sint, t= The equation represents the line tangent to the curve at t= k (Type an exact answer, using radicals as needed.) KS 4 at this point dy TC at t= is dx 4 (Type an exact answer, using radicals as needed.) The value of

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Using the parametric equations we have x 6cost 6cos4 32 y 6sint 6sin4 32 So the point on the curv... blur-text-image

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