Find each of the shaded areas under the standard normal curve using a TI-84 Plus calculator. Round the answers to at least four decimal places. Part: 0 / 4 Part 1 of 4 (a) 0.61 The area of the shaded region is XFind each of the shaded areas under the standard normal curve using a TI-84 Plus calculator. Round the answers to at least four decimal places. Part: 0 / 4 Part 1 of 4 (a) 0.61 The area of the shaded region is XUse the TI-84 Plus calculator to find the =-score for which the area to its left is 0.85 . Round the answer to two decimal places. The :-score for the given area is XUse the TI-84 Plus calculator to find the :-score for which the area to its right is 0.09 . Round the answer to two decimal places. The :-score for the given area is XUse the TI-84 Plus calculator to find the s-scores that bound the middle 66 % of the area under the standard normal curve. Enter the answers in ascending order and round to two decimal places. The :-scores for the given area are andA normal distribution has mean u. = $7 and standard deviation o = 20. Find and interpret the :-score for x = 54. The :-score for x = $4 is . 50 34 15 standard deviations (Choose one) the mean L = 37.A normal population has mean u = $3 and standard deviation o = 6. What is the 86th percentile of the population? Use the TI-84 Plus calculator. Round the answer to at least one decimal place. The $6th percentile of the population is XCheck our blood pressure: In a recent study, the Centers for Disease Control and prevention reported that diastolic blood pressures of adult women in the United States are approximately normally distributed with mean 80.1 mmNg and a standard deviation of 9.5 mmHg. Round the answers to four decimal places. Part: 0 / 4 Part 1 of 4 (3) What proportion of women have blood pressures lower than 62 mmHg? The proportion of women who have blood pressures lower than 62 mmHg isBaby weights: The weight of male babies less than _ months old in the United States is normally distributed with mean 12.3 pounds and standard deviation 3.8 pounds. (a) Find the $+th percentile of the baby weights. (b) Find the 11 th percentile of the baby weights. (c) Find the third quartile of the baby weights. Use the TI-84 Plus calculator and round the answers to at least two decimal places. Part 1 of 3 The 84th percentile of the baby weights is pounds. X Part 2 of 3 The 11 th percentile of the baby weights is pounds. X Part 3 of 3 The third quartile of the baby weights is pounds. XBig chickens: According to a poultry industry news website, the weights of broilers (commercially raised chickens) are approximately normally distributed with mean 1423 grams and standard deviation 169 grams. Use the @ Cumulative Normal Distribution Table to answer the following. (a) What proportion of broilers weigh between 1180 and 1280 grams? (b) What is the probability that a randomly selected broiler weighs more than 1500 grams? (c) Is it unusual for a broiler to weigh more than 1750 grams? Round the answers to at least four decimal places.Fish story: According to a report by the U.S. Fish and Wildlife Service, the mean length of six-year-old rainbow trout in the Arolik River in Alaska is 480 millimeters with a standard deviation of 40 millimeters. Assume these lengths are normally distributed. Round the answers to at least two decimal places. (a) Find the 56" percentile of the lengths. (b) Find the $5 "percentile of the lengths. (c) Find the first quartile of the lengths. (d) A size limit is to be put on trout that are caught. What should the size limit be so that 15 do of six-year-old trout have lengths shorter than the limit? Part: 0 / 4 Part 1 of 4 Find the 56" percentile of the lengths. The 56" percentile of the lengths is XTree heights: Cherry trees in a certain orchard have heights that are normally distributed with mean u = 113 inches and standard deviation o = 17 inches. Round the answers to four decimal places. Part: 0 / 3 Part 1 of 3 (a) What proportion of trees are more than 120 inches tall? The proportion of trees that are more than 120 is XHow much do you study? A survey among freshmen at a certain university revealed that the number of hours spent studying the week before final exams was normally distributed with mean 24 and standard deviation S. Use the TI-84 PLUS calculator to answer the following. Round the answers to at least two decimal places. Part: 0 / 3 Part 1 of 3 (a) Find the 94 percentile of the number of hours studying. The 94" percentile of the number of hours studying is hours. X 5