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Find if '(a). 7t+19 t = ) t+6 To find 1' '(a), we will use the formula II _' tfa {Eltill; ta ' Since t)

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Find if '(a). 7t+19 t = ) t+6 To find 1' '(a), we will use the formula II _' tfa {Eltill; ta ' Since t) = we have 7t+ 1.9 7a+19 f'(a)= im t+6 a+6. fDa ta Putting the fractions in the numerator over a common denominator and simplifying, we have 7r+19 _ 7a+19 = (7t+19)(|:| )(7a+19)(t+6) t+6 a +6 (I + 6)(a + 6) 7ta + 19a + 42t + 114 7at 19E 42a 114 (t + 6)(a + 6) _ (l |)r(| |)a. (t + 6)(a + 6)

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