Find the absolute extreme values of the function on the interval. f(x)=ex-x, -45xs2 O A. Minimum value is 1 at x = 0; maximum value is e -4 + 4 at x = -4 O B. Minimum value is 1 at x = 0; no maximum value O C. Minimum value is 1 at x = 0; maximum value is e 2 - 2 at x =2 O D. Minimum value is e 74 + 4 at x = - 4; maximum value is e 2 - 2 at x = 2