Find the answer to b using the formula and the data given

Summary Temperature ition Count Mean 98.935 Median 98.800 MidRange 98.600 n 15 and 40 50, the t StdDev 0.6539 Range 2.800 ratu IntQRange 1.050 e is Print Done b) Find a 90% confidence interval for the mean body temperature. While the formulas shown below, where y is the sample mean, SE(y) is the standard error of the mean, s is the sample standard deviation, n is the sample size, and to_ , is the critical value for the confidence level with n - 1 degrees of freedom, can be used to calculate the values in the confidence interval, for this problem, use technology. yetn-1 x SE(y) where SE(y) =