Find the appropriate rejection regions for the large-sample test statisticz in these cases. (Round your answers to two decimal places. It the test is one-tailed, enter NONE for the unused region.) (a) A right-tailed test with :7 = 0.01 n: u: (b) A two-tailed test at the 5% significance level n: H: You may need to use the appropriate appendix table or technology to answer this question. Find the appropriate rejection regions for the large-sample test statistic z in these cases. (a) A left-tailed test at the 5% signicance level. [Round your answers to two decimal places. If the test is onetailed, enter NONE for the unused region.) 2: 2.: (b) A twotailed test with a = 0.01. [Round your answers to two decimal places. If the test is one-tailed, enter NONE for the unused region.) > |:| 27 0 H041: 27 versus Ha: In > 27 0 H01\": 27' versus Ha: tr 1 27 O HO: if e 27 versus Ha: _u = 27 Find the test statistic and the p-value. (Round your test statistic to two decimal places and your p-value to four decimal places.) 2 = |:| State your conclusion. 0 The p-value is greater than alpha, so Ho is not rejected. There is sufficient evidence to indicate that the mean is different from 27. O The p-value is greater than alpha, 50 H0 is not rejected. There is insufficient evidence to indicate that the mean is different from 27. O The p-vaiue is less than alpha, so HD is rejected. There is insufficient evidence to indicate that the mean is different from 27. O The p-value is less than alpha, so Ho is rejected. There is sufl'i cient evidence to indicate that the mean is different from 27. The meat department of a local supermarket chain packages ground beef in trays of two sizes. The smaller tray is intended to hold 1 kilogram (kg) of meat. A random sample of 40 packages in the smaller meat tray produced weight measurements with an average of 1.01 kg and a standard deviation of 19 grams. (a) If you were the quality control manager and wanted to make sure that the average amount of ground beef was indeed 1 kg, what hypotheses would you test? O Ho: u = 1 versus Ha : M > 1 O Ho: u 1 O Ho: u = 1 versus Ha: u = 1 O Ho: M = 1 versus Ha: H