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Find the area of the surface generated by revolving the curve about the given axis. (round to two decimal places.) Given: x = 1/6( t
Find the area of the surface generated by revolving the curve about the given axis. (round to two decimal places.)
Given: x = 1/6(t3 ), y = 2t + 1, 1 <= t <= 2, y-axis
Please provide steps and explanation. Thank you!
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