Find the component form of v given its magnitude and the angle it makes with the positive Xaxis. \"v" = 4, 6' = 0 Submit Amwer Find the component form of u + 1: given the lengths of u and v and the angles that u and u make with the positive xaxis. ||U||=3. 9u=0 IIVII =2, 9v=600 u+v= X Submit Answer ' Find the vector v with the given magnitude and the same direction as u. Magnitude Direction \"v\" = 81 u = (0, 3, 3) Determine whether u and v are orthogonal, parallel, or neither. u = (cos(9), sin(9), 7) v = (sin(6), cos(6), O) 0 parallel O orthogonal O neither Subunit Answer Consider the following. u = -8i - 4j - 2k, v = 2j + 2k (a) Find the projection of u onto v. -3 j + k X (b) Find the vector component of u orthogonal to v. -8i -j + k X Find sets of parametric equations and symmetric equations of the line that passes through the given point and is parallel to the given vector or line. (For each line, write the direction numbers as integers.) Point Parallel to (-9, 0, 6) v - 7i + 9j - 2k (a) parametric equations (Enter your answers as a comma-separated list.) x = (9i + j + 6k) + A(7i + 9j - 2k) (b) symmetric equations x+9 =- 6 - OZZY= O X-9 = =5 0 7x = = 2z I sets of parametric equation ic equations and symmetric equations of the line that passes through the two points (if possible). (For each line, write the nbers as integers.) (5, - 3, -2). (=2. 2.1) (a) parametric equations (Enter your answers as a comma-separated list.) 17 + 5, 11 - 3, 9 -2 (b) symmetric equations = =2+2 0 3-X -y - 2+2 0 472 = 1 2 =2 11 Submit Answer Viewing Saved Work Revert to Last ResponseFind the point(s) of intersection (if any) of the plane and the line. (If an answer does not exist, enter DNE.) 3 x + 4y = - 7, x - 2 = * = 2-5 ( x, y, z ) = ( Determine whether the line lies in the plane. The line ---Select--- |lie in the plane. -Select- does does not Submit