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Find the derivative of the following function. (203 - 20 + 2) 2 y = (3x + 4)5 Solution Apply the Quotient Rule and the

Find the derivative of the following function. (203 - 20 + 2) 2 y = (3x + 4)5 Solution Apply the Quotient Rule and the Chain Rule: = (3x+4)' (2) (23 -2+2) (3x2-1) -(5) (3x+4) (3) (23-2+2) (32+4) 10 = (3x+4)4 (23 -x+2) [(2) (3x+4) (32-1) -(15) (23 -2+2)] (3x+4)10 = (a3 -2+2) (2) (923-3x+12x2-4)-15x3+15x-30 (3x+4) = (23 -x+2) 18x3 -6:+24x2-8-15x3+15x-30] (3x+4) = (23 -2+2) [3ac3 +24x2+9x-38 (3x+4)

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