Find the derivative of the following function. Question list K y= - 210x2 - 1 Question 1 dy dx = - 20x In (2)2 10x2 - 1Researchers have found that the risk of coronary heart disease rises as blood cholesterol increases. This risk may be QueStlon \"St '6 approximated by the function R(c) = 3.189(1.006)C, 100 SCSSOO, where R is the risk in terms of coronary heart disease incidence per 1000 per year, and c is the cholesterol in mg/dL. Suppose a person's cholesterol is 181 mg/dL and going up at a rate of 15 mg/dL per year. At what rate is the person's risk of coronary heart disease going up? 0 Question 1 _ The person's risk of coronary heart disease is going up at the rate of 0.056' coronary heart disease incidence per 1000 o QueStfon 2 per year per mg/dL of cholesterol. (Round to three decimal places as needed.) Find the derivative of the function. Question list I? y: 6x|n(9x+2) o Question1 _ 54x dx 6In(9x+2) 9x+2 9 Question 2 0 Question 3 The field metabolic rate (FMR), or the total energy expenditure per day in excess of growth, can be calculated for pronghorn fawns using Nagy's formula, F(x) = 0.774 + 0.727 log x, where x is the mass (in grams) of the fawn and F(x) is the energy expenditure (in kJ/day). a. Determine the total energy expenditure per day in excess of growth for a pronghorn fawn that weighs 21,000 g. b. Find F'(21,000) and interpret the results. c. Graph the function on [5000,30000] by [3,5]. . . . a. The total energy expenditure per day in excess of growth for a pronghorn fawn with a mass of 21,000 g is 3.9 KJ day (Type an integer or decimal rounded to the nearest tenth as needed.) b. Determine F' (x). 0.727 F' (X) = ( In 10)x (Type an exact answer.) Find F'(21,000) and interpret the results. F'(21,000) = 1.5x 10 ; when a fawn is 21 kg in mass, the rate of change of energy expenditure of the fawn is KJ about 1.5x 10-5 per gram. day (Use scientific notation. Use the multiplication symbol in the math palette as needed. Round to one decimal place as needed.) c. Graph F(x) on [5000,30000] by [3,5]. Choose the correct graph below.Recall that the slope of the tangent line to a graph is given by the derivative of the function. Find the slope of the line 71: tangent to the graph of y = cos 5x at x = E. E) The slope of the line tangent to the graph at x = E is (Type an exact answer using radicals as needed.) ' Ta: 5 2 2 . A particle moves along a straight line. The distance of the particle from the origin at time t is given by s(t) = sin t + 2 cos t. 31: 31: Find the velocity at the following times. a. t=0 b. t= T c. t= E E) a. The velocity at time 0 is 1'. (Type an exact answer, using radicals as needed.) ' 3:: 345 b. The velocity at time T is 2 . (Type an exact answer, using radicals as needed.) 3n: .. c. The velocity at time 3 is 2 . (Type an exact answer, using radicals as needed.) Suppose a certain drug is administered to a patient, with the percent of concentration of the drug in the bloodstream t hours later given by the following function, where 0