Find the derivative with respect to x if f(x) = (8x- - 16x + 16) ex y = [(x) . g'( x) + f'(x)g(x) Apply this to the given function f(x) = (8x2 - 16x + 16) ex f'(x) = (8x2 -16x +16) ex + ex( 16x-16 (Simplify your answer. Do not factor.) Therefore, the derivative with respect to x for f(x) = (8x -16x + 16) ex is f' (x) = 8x ex (Simplify your answer.)