Find the distance from the point (0,0,7) to the line x = -3t, y = - 2t, and z = - 2t The cross product used when calculating the distance is (0,0,7) x (-3,-2,-2) = (14,-21,0). The magnitude of the cross product is /637 (Type an exact answer, using radicals as needed.) The distance is (Type an exact answer, using radicals as needed.)