Find the distance from the point Q(1,2, - 2) to the plane 2x - 7z =7. (Note that if P is a point on the plane ax + by + cz =d, then the distance from any point Q to the plane equals the length of the orthogonal projection of PQ onto a vector n = (a,b,c) normal to the plane. |PQ . n This can be expressed as d = In The distance is (Type an exact answer, using radicals as needed.)