Find the end to end delay including the transmission delays and propagation delays on each of the three links, but ignoring queueing delays and processing delays from when the left host begins transmitting the first bit of a packet to the time when the last bit of that packet is received at the server at the right. The speed of light propagation delay on each link is 3x10^8 m/sec. Assume a packet length of 1000 bytes.

Fill in the values in the equations below, use SI units bps, m, m/sec, write all the zeros do not use the scientific/short form

when you fill in the values, and give your answers in milliseconds ms with 2 decimal places e.g. 1234.56

+ Link 1- Link 2 +Link 3- Transmission rate: 11 Mbps Link Length: 75 km Transmission rate: 20 Mbps Link Length: 50 km Transmission rate: 512 kbps Link Length: 500 km Find the end-to-end delay (including the transmission delays and propagation delays on each of the three links, but ignoring queueing delays and processing delays) from when the left host begins transmitting the first bit of a packet to the time when the last bit of that packet is received at the server at the right. The speed of light propagation delay on each link is 3x10^8 m/sec. Assume a packet length of 1000 bytes. Fill in the values in the equations below, use SI units (bps, m, m/sec, write all the zeros - do not use the scientific/short form) when you fill in the values, and give your answers in milliseconds (ms) with 2 decimal places (e.g. 1234.56) (5 points). Link 1 transmission delay = = ms Link 1 propagation delay = = ms Link 2 transmission delay = = ms Link 2 propagation delay = 1 = ms Link 3 transmission delay = = ms Link 3 propagation delay = ms Thus, the total end-to-end delay is the sum of these six delays: ms